Home
Class 12
CHEMISTRY
The solubility of barium sulphate at 298...

The solubility of barium sulphate at 298 K is `1.1 xx10^(-5) mol L^(-1)`. Calculate the solubility product of barium sulphate at the same temperature .

Text Solution

AI Generated Solution

To calculate the solubility product (Ksp) of barium sulfate (BaSO4) at 298 K, we can follow these steps: ### Step 1: Write the Dissociation Equation Barium sulfate dissociates in water according to the following equation: \[ \text{BaSO}_4 (s) \rightleftharpoons \text{Ba}^{2+} (aq) + \text{SO}_4^{2-} (aq) \] ### Step 2: Define Solubility Let the solubility of barium sulfate be represented by \( S \). According to the problem, the solubility \( S \) is given as: ...
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    AAKASH INSTITUTE|Exercise Assignment (SECTION-A) (SUBJECTIVE TYPE QUESTIONS(ONE OPTION IS CORRECT)|45 Videos
  • EQUILIBRIUM

    AAKASH INSTITUTE|Exercise Assignment (SECTION-B)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT)|20 Videos
  • EQUILIBRIUM

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION -D)|20 Videos
  • ENVIRONMENTAL CHEMISTRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D) (Assertion - Reason Type Questions)|5 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    AAKASH INSTITUTE|Exercise Assignment (Section-D) Assertion-Reason Type Question|15 Videos

Similar Questions

Explore conceptually related problems

The solubilty of barium sulphate at 298 K is 1.1 xx 10^(-5) "mol " L^(-1) . Calculate the solubilty product of barium sulphate at the same temerature.

The solubility of silver chromate Ag_2CrO_4 is 8.0 xx 10^(-5) " mol L"^(-1) . Calculate the solubility product.

The solubility of AgBr in water is 1.20 xx 10-5 mol dm ^-3 . Calculate the solubility product of Ag Br.

The molar solubility of silver sulphate is 1.5xx10^(-2)mol L^(-1) . The solubility product of the salt will be

The solubility of AgCl in water at 298 K is 1.06xx10^(-5) mle per litre. Calculate its solubility product at this temperature.

The solubility of a springly soluble salt AB_(2) in water is 1.0xx10^(-5) mol L^(-1) . Its solubility product is:

The solubility of SrF_2 in water is 1.2 xx 10^(-2)g L^(-1) . Calculate the solubility product of the salt at room temperature (molecular mass of SrF_2 = 125.6).

AAKASH INSTITUTE-EQUILIBRIUM-TRY YOURSELF
  1. The value of DeltaG^(ɵ) for the phosphorylation of glycose in glycolys...

    Text Solution

    |

  2. Hydrolysis of sucrose gives "Sucrose" +H(2)OhArr"Glucose + Fructose"...

    Text Solution

    |

  3. The following system is in equilibrium SO2CI2+ "Heat' hArr SO2+CI2 W...

    Text Solution

    |

  4. Mention atleast three ways by which the concentration of SO(2)(g) be i...

    Text Solution

    |

  5. Name a species which can act as both conjugate acid and conjugate base...

    Text Solution

    |

  6. BCl(3) behavs a a Lewis acid Give reason.

    Text Solution

    |

  7. Calculate the pH of N/(1000) sodium hydroxide (NaOH) solution assuming...

    Text Solution

    |

  8. 13.5 g of an acid HA of molecular mass 135 was dissolved in 10 litres ...

    Text Solution

    |

  9. Calculate the H^+ ion concentration in 0.10 M acetic acid solution- Gi...

    Text Solution

    |

  10. When 0.1 mole of NH(3) is dissolved in water to make 1.0 L of solutio...

    Text Solution

    |

  11. If ionisation constant of an acid (HA) at equilibrium is 1.0xx10^(-8) ...

    Text Solution

    |

  12. Calcuate the degree of ionisation and pH of 0.05 M solution of a weak ...

    Text Solution

    |

  13. The ionization constnt of (C(2)H(5))(3)N is 6.4xx10^(-5). Calculate it...

    Text Solution

    |

  14. Calculate the pH of 0.033 M ammonia solution if 0.033 M NH(4)Cl is int...

    Text Solution

    |

  15. Calculate the pH of 0.01 M solution of NH(4)CN. The dissociation const...

    Text Solution

    |

  16. One litre of 0.05 M HCl was completely neutralized by NaOH. Calcuate t...

    Text Solution

    |

  17. The solubility of barium sulphate at 298 K is 1.1 xx10^(-5) mol L^(-1)...

    Text Solution

    |

  18. 20 ml of 1.5 xx10^(-5) M BaCI2 solution is mixed with 40 ml of 0.9 xx ...

    Text Solution

    |

  19. Calculate solubility product of Hg(2)Cl(2) if its solubility at room t...

    Text Solution

    |

  20. NaCI solution is added to a saturated solution of PbCI2 . What will ha...

    Text Solution

    |