20 ml of `1.5 xx10^(-5) M BaCI_2` solution is mixed with 40 ml of `0.9 xx 10^(-5)`M sodium sulphate solution , will a precipitate of `BaSO_4` get formed ?
`(K_(sp) "for" BaSO_4 =1.2 xx 10^(-10))`.

Explanation

To determine whether a precipitate of BaSO₄ will form when mixing 20 mL of 1.5 x 10⁻⁵ M BaCl₂ with 40 mL of 0.9 x 10⁻⁵ M Na₂SO₄, we need to follow these steps:

### Step 1: Calculate the moles of BaCl₂ and Na₂SO₄

1. **Moles of BaCl₂**:
\[ \text{Molarity} = \frac{\text{Moles}}{\text{Volume (L)}} \]
...