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In a closed system : A(s)hArr 2B(g)+3C, ...

In a closed system : `A(s)hArr 2B(g)+3C`, if the partial pressure of C is doubled, then partial pressure of B will be

A

Twice the orignal pressure

B

Halfof its original pressure

C

`1/(2sqrt2)` times the original pressure

D

`2sqrt2` times its original pressure

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • In a closed system, A(s) hArr 2B(g) + 3C(g) , if partial pressure of C is doubled, then partial pressure of B will be

    A
    `2sqrt2` times the original value
    B
    `1/2` times the original value
    C
    2 times the original value
    D
    `1/(2sqrt2)` times the original value

  • Temperature pressure and molar concentration are the three factors which can disturb the equilibrium in a reversible reaction. Their effect is governed by Le Chatelier's principle . Whereas high concentration of the reactants always favours the formation of the products irrespective of its nature the effect of temperature and pressure depends upon the nature of the reaction . pressure does not disturb the equilibrium point in a reaction in which the reactants and products have same number of moles in the gaseous state. In a closed system A (s) hArr 2B(g) +3C(g) if partical pressure of C is doubled then partial pressure of B will be :

    A
    `2sqrt(2)` times the original value
    B
    `1/2` times the original value
    C
    2 times of the original value
    D
    `(1)/(2sqrt(2))` times the original value.

  • In a closed system: A(s) hArr 2B(g)+3C(g) , if the partial pressure of C is doubled at equillibrium, then partial pressure of B will be :

    A
    two times the original value
    B
    one-half of its original value
    C
    `(1)/(2sqrt2)` times the original value
    D
    `2sqrt2` times the original value

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