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The compound that is not a Lewis acid...

The compound that is not a Lewis acid

A

`AICI_3`

B

`BF_3`

C

`NF_3`

D

`SnCI_4`

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The correct Answer is:
To determine which compound is not a Lewis acid, we need to understand the definition of Lewis acids and bases. According to Lewis theory, a Lewis acid is a species that can accept a lone pair of electrons, while a Lewis base is a species that can donate a lone pair of electrons. ### Step-by-Step Solution: 1. **Identify the Compounds**: We need to analyze the following compounds: AlCl3, PF3, NF3, and SnCl4. 2. **Analyze AlCl3**: - Aluminum (Al) has the electron configuration: [Ne] 3s² 3p¹. - It can form three bonds with chlorine, and in doing so, it can promote one of its 3s electrons to the 3p orbital. - This results in sp² hybridization, leaving an empty p orbital that can accept a lone pair of electrons from a Lewis base. - **Conclusion**: AlCl3 is a Lewis acid. 3. **Analyze PF3**: - Phosphorus (P) has the electron configuration: [Ne] 3s² 3p³. - In PF3, phosphorus forms three bonds with fluorine, and it has one lone pair remaining. - The empty p orbital can accept a lone pair, making it a potential Lewis acid. - **Conclusion**: PF3 can act as a Lewis acid. 4. **Analyze NF3**: - Nitrogen (N) has the electron configuration: [He] 2s² 2p³. - In NF3, nitrogen forms three bonds with fluorine and retains one lone pair. - There are no empty orbitals available for accepting a lone pair of electrons. - **Conclusion**: NF3 is not a Lewis acid. 5. **Analyze SnCl4**: - Tin (Sn) has the electron configuration: [Kr] 5s² 4d¹⁰ 5p². - In SnCl4, tin can promote electrons and form four bonds with chlorine, resulting in sp³ hybridization. - This leaves empty d orbitals available for accepting electrons. - **Conclusion**: SnCl4 is a Lewis acid. 6. **Final Conclusion**: Among the compounds analyzed, NF3 is the only compound that does not act as a Lewis acid. ### Summary: - AlCl3: Lewis acid - PF3: Lewis acid - NF3: **Not a Lewis acid** - SnCl4: Lewis acid
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