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In the equilibrium SO2CI(g) hArr SO2(g) ...

In the equilibrium `SO_2CI(g) hArr SO_2(g) +CI_2(g)`
at 2000 k and 10 atm pressure , % `CI_2 =% SO_2=40` (by volume) then

A

`K_c=0.1 mol "It"^(-1)`

B

`(n(SO_2CI_2))/(n(SO_2))=1/4` at equilibrium

C

`n(SO_2CI_2)=n(SO_2)=n(CI_2)`

D

`K_p=8` atm

Text Solution

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The correct Answer is:
D
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