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The dissociation equilibrium of a gas AB...

The dissociation equilibrium of a gas `AB_2` can be represented as, `2AB_2(g) hArr 2AB (g) +B_2(g)`. The degree of disssociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant `k_p` and total pressure P is

A

`((K_p)/P)`

B

`((2k_p)/P)`

C

`((2K_p)/P)^(1//3)`

D

`((2K_p)/P)^(1//2)`

Text Solution

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The correct Answer is:
C
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