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A : pH of equimolar solution of NH4 CI a...

A : pH of equimolar solution of `NH_4 CI and NH_4OH` does not change when small amount of HCI is added to it .
R : pOH of above solution is equal to `pK_b` of the buffer.

A

If both Assertion & Reason are true and the reason in the corret explanation of the assertion, then mark

B

If both assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark

C

If Assertion is true statement but Reason is false then mark

D

If both Assertion and Reason are false statements , then mark

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step-by-Step Solution: 1. **Understanding the Components**: - We have an equimolar solution of \( NH_4Cl \) (ammonium chloride) and \( NH_4OH \) (ammonium hydroxide). - \( NH_4Cl \) is a salt that dissociates into \( NH_4^+ \) ions and \( Cl^- \) ions in solution. - \( NH_4OH \) is a weak base that partially dissociates in water. 2. **Buffer Solution**: - The combination of a weak base (\( NH_4OH \)) and its conjugate acid (\( NH_4Cl \)) forms a buffer solution. - A buffer solution resists changes in pH when small amounts of strong acids or bases are added. 3. **Effect of Adding HCl**: - When a small amount of HCl (a strong acid) is added to the buffer solution, the \( H^+ \) ions from HCl react with the \( NH_4OH \) (the weak base) to form \( NH_4^+ \) ions. - This reaction does not significantly change the concentration of \( NH_4OH \) or \( NH_4^+ \), thus the pH of the solution remains relatively constant. 4. **pH and pOH Relationship**: - The pH of the buffer solution can be expressed using the Henderson-Hasselbalch equation: \[ pH = pK_a + \log \left( \frac{[Base]}{[Acid]} \right) \] - In this case, since the concentrations of \( NH_4OH \) and \( NH_4Cl \) are equal, the log term becomes zero, leading to: \[ pH = pK_a \] - Since \( pK_a + pK_b = 14 \) (for water at 25°C), we can say that the pOH of the solution is equal to \( pK_b \) of the buffer. 5. **Conclusion**: - The assertion (A) is true because the pH does not change significantly upon the addition of HCl. - The reason (R) is also true because the pOH of the solution is indeed equal to \( pK_b \) of the buffer. ### Final Answer: Both the assertion (A) and the reason (R) are true, and the reason correctly explains the assertion.
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