Oxidation number of `N` in `(NH_(4))_(2)SO_(4)` is

Explanation

Let the oxidation number of N in `(NH_(4))_(2)SO_(4)` molecule is x.
Now,
`" "2x+1 (+1 times 8)+ 6+(-2 times 4)=0`
`" "2x+8+6-8=0`
`" "x=-3`