How does `Cu_(2)O` act as both oxidant and reductant ?

Explanation

`Cu^(+)` undergoes disproportionation to form `Cu^(2+)` and Cu.
`" "2Cu^(+)(aq) rarr Cu^(2+)(aq)+Cu(s)`
Thus, `Cu^(+) " or " Cu_(2)O` acts both as an oxidant and a reductant.