In passing chlorine gas through a concentrated solution of alkali we get chloride and chlorate ions Obtain balanced chemical equation for this reaction.

Explanation

(ii) `Cl_(2) rarr 2Cl^(-)` (Reduction half)
`" "Cl_(2) rarr 2ClO_(3)^(-)` (Oxidation half)
(iii) Balancing `e^(-)`
`" "Cl_(2)+2e^(-) rarr 2Cl^(-)`
`" "Cl_(2) rarr 2ClO_(3)^(-)+10e^(-)`
(iv) Balancing .O.
`" "Cl_(2)+2e^(-) rarr 2Cl^(-)`
`" " Cl_(2)+6H_(2)O rarr 2ClO_(3)^(-)+10e^(-)`
(v) Balancing .H.
`" "Cl_(2)+2e^(-) rarr 2Cl^(-)`
`" "Cl_(2)+6H_(2)O+12OH^(-) rarr 2ClO_(3)^(-)+10e^(-)+12H_(2)O`
Now,
`" "[Cl_(2)+2e^(-) rarr 2Cl^(-)] times 5`
`Cl_(2)+12OH^(-) rarr 2ClO_(3)^(-)+10e^(-)+6H_(2)O`
`bar(6Cl_(2)+12OH^(-) rarr 10Cl^(-)+2ClO_(3)^(-)+6H_(2)O)`
or `" "3Cl_(2)+6OH^(-) rarr 5Cl^(-)+ClO_(3)^(-)+3H_(2)O`