100 ml of 1M NaOH is mixed with 50ml of 1N KOH solution. Normality of mixture is

Options

A. 1N
B. 0.5 N
C. 0.25 N
D. 2 N

Answer

To find the normality of the mixture when 100 ml of 1M NaOH is mixed with 50 ml of 1N KOH, we can follow these steps:

### Step 1: Calculate the millimoles of NaOH
- Molarity (M) = moles/volume (L)
- For NaOH:
- Molarity = 1 M
- Volume = 100 ml = 0.1 L
- Millimoles of NaOH = Molarity × Volume (in ml)

\[ \text{Millimoles of NaOH} = 1 \, \text{M} \times 100 \, \text{ml} = 100 \, \text{mmol} \]

### Step 2: Calculate the millimoles of KOH
- Normality (N) = moles of equivalent solute/volume (L)
- For KOH:
- Normality = 1 N
- Volume = 50 ml = 0.05 L
- Since KOH is a strong base and provides 1 OH⁻ ion, its normality is equal to its molarity.

\[ \text{Millimoles of KOH} = 1 \, \text{N} \times 50 \, \text{ml} = 50 \, \text{mmol} \]

### Step 3: Calculate the total millimoles in the mixture
- Total millimoles = Millimoles of NaOH + Millimoles of KOH

\[ \text{Total millimoles} = 100 \, \text{mmol} + 50 \, \text{mmol} = 150 \, \text{mmol} \]

### Step 4: Calculate the total volume of the mixture
- Total volume = Volume of NaOH + Volume of KOH

\[ \text{Total volume} = 100 \, \text{ml} + 50 \, \text{ml} = 150 \, \text{ml} \]

### Step 5: Calculate the molarity of the mixture
- Molarity (M) = Total millimoles / Total volume (in ml)

\[ \text{Molarity of mixture} = \frac{150 \, \text{mmol}}{150 \, \text{ml}} = 1 \, \text{M} \]

### Step 6: Calculate the normality of the mixture
- Since both NaOH and KOH are monovalent bases, their normality is equal to their molarity.

\[ \text{Normality of mixture} = 1 \, \text{N} \]

### Final Answer:
The normality of the mixture is **1 N**.

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