A mixture of two liquids A and B having boiling points of A is `70^@C` and boiling point of B is `100^@C` distills at `101.2^@C` as single liquid, hence this mixture is

Options

A. Ideal solution
B. Non ideal solution showing +ve deviation
C. Non ideal solution showing -ve deviation
D. Immiscible solution

Answer

To solve the problem, we need to analyze the information given about the mixture of two liquids A and B, their boiling points, and the boiling point of the mixture.

### Step-by-Step Solution:

1. **Identify the Boiling Points:**
- The boiling point of liquid A is given as 70°C.
- The boiling point of liquid B is given as 100°C.
- The boiling point of the mixture is given as 101.2°C.

2. **Compare the Boiling Point of the Mixture with Individual Components:**
- The boiling point of the mixture (101.2°C) is higher than the boiling points of both A (70°C) and B (100°C).
- This indicates that the mixture does not behave ideally.

3. **Understand the Implications of the Boiling Point:**
- Since the boiling point of the mixture is higher than both pure components, it suggests that the vapor pressure of the mixture is lower than that of the individual components.
- This is indicative of a non-ideal solution.

4. **Determine the Type of Non-Ideal Solution:**
- In non-ideal solutions, if the boiling point of the mixture is higher than that of the individual components, it indicates a negative deviation from Raoult's law.
- Negative deviation occurs due to strong intermolecular forces (adhesive forces) between the components of the mixture, which leads to a lower vapor pressure.

5. **Conclusion:**
- Therefore, the mixture of liquids A and B is classified as a non-ideal solution showing negative deviation.

### Final Answer:
The mixture is a non-ideal solution showing negative deviation.