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Correct order of freezing point of given...

Correct order of freezing point of given solution
I. 0.1 M glucose II. 0.2 M urea III.0.1 M NaCl IV. `0.05 M CaCl_2`

A

`I lt II lt III lt IV`

B

`I gt II gt III gt IV`

C

`III=II lt IV lt I`

D

`IV gt II gt III gt I`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of freezing points of the given solutions, we need to calculate the depression in freezing point (ΔTf) for each solution using the formula: \[ \Delta T_f = i \cdot K_f \cdot m \] Where: - \(i\) = van 't Hoff factor (number of particles the solute breaks into) - \(K_f\) = freezing point depression constant (which is constant for a given solvent) - \(m\) = molality of the solution (we'll use molarity here as a simplification since the problem gives us molarity) Since \(K_f\) is constant for all solutions, we can compare the values of \(i \cdot m\) for each solution to determine the order of freezing points. ### Step 1: Calculate \(i \cdot m\) for each solution 1. **Glucose (0.1 M)**: - Glucose does not dissociate in solution, so \(i = 1\). - \(i \cdot m = 1 \cdot 0.1 = 0.1\) 2. **Urea (0.2 M)**: - Urea also does not dissociate, so \(i = 1\). - \(i \cdot m = 1 \cdot 0.2 = 0.2\) 3. **NaCl (0.1 M)**: - NaCl dissociates into two ions: Na\(^+\) and Cl\(^-\), so \(i = 2\). - \(i \cdot m = 2 \cdot 0.1 = 0.2\) 4. **CaCl₂ (0.05 M)**: - CaCl₂ dissociates into three ions: Ca\(^{2+}\) and 2 Cl\(^-\), so \(i = 3\). - \(i \cdot m = 3 \cdot 0.05 = 0.15\) ### Step 2: Summarize the results - Glucose: \(i \cdot m = 0.1\) - Urea: \(i \cdot m = 0.2\) - NaCl: \(i \cdot m = 0.2\) - CaCl₂: \(i \cdot m = 0.15\) ### Step 3: Determine the order of freezing points The freezing point depression is directly related to the value of \(i \cdot m\): - The larger the value of \(i \cdot m\), the greater the depression in freezing point (lower freezing point). - Therefore, the order of freezing points from highest to lowest is: - Glucose (0.1) - CaCl₂ (0.15) - Urea (0.2) - NaCl (0.2) Since Urea and NaCl have the same \(i \cdot m\), they will have the same freezing point. ### Final Order of Freezing Points: 1. Glucose (highest freezing point) 2. CaCl₂ 3. Urea = NaCl (lowest freezing point)
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