The conductivity of 0.35M solution of KCl at 300K is 0.0275 S `cm^(-1)`. Calculate molar conductivity

Explanation

To calculate the molar conductivity of a 0.35 M solution of KCl, we can use the relationship between conductivity (κ), molar conductivity (Λm), and concentration (C). The formula for molar conductivity is given by:

\[ \Lambda_m = \frac{\kappa}{C} \]

Where:
- \(\Lambda_m\) = molar conductivity (in S cm²/mol)
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