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The resistance of 0.01M CH(3)COOH soluti...

The resistance of 0.01M `CH_(3)COOH` solution is found to be 2220 ohm when measured in a cell of cell constant 0.366 `cm^(-1)` Given that `lambda_(m)^(@)(H^(+)) and lambda_(m)^(@)(cH_(3)COO^(-))` as 349.1 and 40.9 `cm^(2) mol^(-1)` calculate
(a) Conductivity
(b) Molar Conductance
(c) Degree of dissociation
(d) Dissociation Constant

Text Solution

Verified by Experts

`lamda_(m)^(@) (CH_(3)COOH) = lamda_(m)^(@) (H^(+)) + lamda_(m)^(@) (CH_(3)COO^(-))`
`=349.1 + 40.9 = 390.0 S cm^(2) mol^(-1)`
(a) Conductivity `= ("Cell constant")/("Resistance") = (0.366)/(2220) = 1.648 xx 10^(-4) S cm^(-1)`
(b) `Lamda_(m) = ("Conductivity" xx 1000)/("Molarity") = (1.648 xx 10^(-4) xx1000)/(0.01) = 16.48 S cm^(-1) mol^(-1)`
(c ) `alpha = (lamda_(m))/(Lamda_(m)^(@)) = 0.0422`
(d) `K_(a) = (Calpha^(2))/(1 -alpha) = C alpha^(2) = 0.01 (0.0422)^(2) = 1.78 xx 10^(-5)`
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