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A current of 2A was passed for 1.5 hours...

A current of 2A was passed for 1.5 hours through a solution of `CuSO_(4)` when 1.6g of copper was deposited. Calculate percentage current efficiency.

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To calculate the percentage current efficiency of the electrolysis process where a current of 2A was passed for 1.5 hours through a solution of CuSO₄, resulting in the deposition of 1.6g of copper, we can follow these steps: ### Step 1: Calculate the total charge (Q) passed through the solution. The formula for charge is given by: \[ Q = I \times t \] where: - \( I \) = current in amperes (A) - \( t \) = time in seconds (s) ...
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