Calculate the emf of the cell in which the following reaction takes place
`Ni(s) + 2Ag_((0.002M))^(+) rarr Ni_((0.160M))^(2+) + 2Ag_((s))`
Given `E_("Cell")^(@) = 1.07V`

Explanation

To calculate the EMF (Electromotive Force) of the cell for the given reaction:

**Reaction:**
\[ \text{Ni(s)} + 2\text{Ag}^+_{(0.002M)} \rightarrow \text{Ni}^{2+}_{(0.160M)} + 2\text{Ag(s)} \]

**Given:**
- Standard EMF of the cell, \( E^\circ_{\text{cell}} = 1.07 \, \text{V} \)

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