Find out given cell is spontaneous or non-spontaneous
`underset(P_(1))(H_(2)//H^(@)) || underset(P_(2))(H^(+)//H_(2))`. If `P_(1) gt P_(2)`

Explanation

To determine whether the given electrochemical cell is spontaneous or non-spontaneous, we can follow these steps:

### Step 1: Identify the Cell Components
The cell is represented as:
\[ \text{P}_{1}(\text{H}_{2} // \text{H}^{+}) || \text{P}_{2}(\text{H}^{+} // \text{H}_{2}) \]
This indicates that both electrodes are hydrogen electrodes, where:
- Electrode 1 (left side) has hydrogen gas at pressure \( P_1 \) and \( \text{H}^{+} \) ions.
- Electrode 2 (right side) has \( \text{H}^{+} \) ions and hydrogen gas at pressure \( P_2 \).
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