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The conductivity of four electrolytes P,...

The conductivity of four electrolytes P, Q, R, S in `ohm^(-1) cm^(-1)` area as follows `P (5 xx 10^(-6)), Q (1 xx 10^(-10)), R (7 xx 10^(-8)), S(9.2 xx 10^(-3))`. The one which offers highest resistance to the passage of electric current is

A

P

B

S

C

R

D

Q

Text Solution

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The correct Answer is:
To determine which electrolyte offers the highest resistance to the passage of electric current, we need to understand the relationship between conductivity and resistance. Here’s a step-by-step solution: ### Step 1: Understand the relationship between conductivity and resistance Conductivity (κ) is inversely related to resistance (R). This means that as conductivity increases, resistance decreases, and vice versa. The relationship can be expressed as: \[ R = \frac{1}{κ} \] ### Step 2: List the conductivities of the electrolytes We have the following conductivities for the electrolytes: - P: \( 5 \times 10^{-6} \, \text{ohm}^{-1} \text{cm}^{-1} \) - Q: \( 1 \times 10^{-10} \, \text{ohm}^{-1} \text{cm}^{-1} \) - R: \( 7 \times 10^{-8} \, \text{ohm}^{-1} \text{cm}^{-1} \) - S: \( 9.2 \times 10^{-3} \, \text{ohm}^{-1} \text{cm}^{-1} \) ### Step 3: Identify the electrolyte with the lowest conductivity To find the electrolyte with the highest resistance, we need to identify which electrolyte has the lowest conductivity. We can compare the values: - \( 5 \times 10^{-6} \) - \( 1 \times 10^{-10} \) - \( 7 \times 10^{-8} \) - \( 9.2 \times 10^{-3} \) ### Step 4: Compare the conductivities From the values listed: - \( 1 \times 10^{-10} \) (Q) is the smallest value. ### Step 5: Conclusion Since Q has the lowest conductivity, it will have the highest resistance. Therefore, the electrolyte that offers the highest resistance to the passage of electric current is: **Q (1 x 10^(-10) ohm^(-1) cm^(-1))** ---
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