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The emf of a Daniell cell at 298 K is E1...

The emf of a Daniell cell at `298 K` is `E_1 Zn underset((0.01M))|NnSO_4 |underset((1.0M))| CuSO_4 | Cu` when the concentration of
`ZnSO_4` is `1.0 M` and that of `CuSO_4` is `0.01 M` the emf changed to `E_2` what is the relationship between ` E_1` and `E_2` .

A

`E_(1) gt E_(2)`

B

`E_(1) lt E_(2)`

C

`E_(1) = E_(2)`

D

`E_(2) = 0 ne E_(1)`

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The correct Answer is:
A
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