The ratio of moles of water as water of crystallisation in LiCl and `BaCl_(2)` is

Options

A. `1 : 1`
B. `1 : 2`
C. `1 : 4`
D. `1 : 3`

Answer

To find the ratio of moles of water as water of crystallization in LiCl and BaCl₂, we need to follow these steps:

### Step 1: Identify the chemical formulas
- For Lithium Chloride (LiCl), the hydrated form is LiCl·2H₂O.
- For Barium Chloride (BaCl₂), the hydrated form is BaCl₂·2H₂O.

### Step 2: Determine the moles of water in each compound
- In LiCl·2H₂O, there are **2 moles of water**.
- In BaCl₂·2H₂O, there are also **2 moles of water**.

### Step 3: Calculate the ratio of moles of water
- The ratio of moles of water in LiCl to that in BaCl₂ is:

\[ \text{Ratio} = \frac{\text{Moles of water in LiCl}}{\text{Moles of water in BaCl₂}} = \frac{2}{2} = 1 \]

### Step 4: Write the final answer
- Therefore, the ratio of moles of water as water of crystallization in LiCl and BaCl₂ is **1:1**.

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