`S_(8)` ring of both rhombic sulphur and monoclinic sulphur has crown shaped structure . The S- S -S bond angle in `S_(8)` ring is

Options

A. `109^(@)` 28'
B. `107^(@)`
C. `104^(@)`
D. `120^(@)`

Answer

To find the S-S-S bond angle in the crown-shaped structure of the \( S_8 \) ring in both rhombic and monoclinic sulfur, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of \( S_8 \)**:
- The \( S_8 \) molecule consists of eight sulfur atoms arranged in a crown-shaped cyclic structure. This structure can be visualized as a ring where the atoms are positioned in a way that resembles a crown.

2. **Visualize the Crown Shape**:
- In the crown-shaped \( S_8 \) structure, the sulfur atoms are not in a flat plane. Instead, they adopt a three-dimensional arrangement that creates a "crown" effect. This affects the bond angles between the sulfur atoms.

3. **Identify the Bond Angles**:
- The bond angle in question is the angle formed between two adjacent sulfur atoms in the \( S_8 \) ring. In the crown-shaped structure, the S-S-S bond angle is not the typical tetrahedral angle (109.5°) due to the specific arrangement of the atoms.

4. **Determine the S-S-S Bond Angle**:
- Based on the known structural data of \( S_8 \), the S-S-S bond angle in the crown-shaped structure is approximately \( 107° \).

5. **Conclusion**:
- Therefore, the S-S-S bond angle in the \( S_8 \) ring of both rhombic and monoclinic sulfur is \( 107° \).

### Final Answer:
The S-S-S bond angle in the \( S_8 \) ring is \( 107° \).

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