What is the product when Mg react with `SO_(2)` ?

Options

A. Mg O
B. `MgSO_(4)`
C. Mg S
D. Both (1) & (3)

Answer

To determine the products when magnesium (Mg) reacts with sulfur dioxide (SO₂), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are magnesium (Mg) and sulfur dioxide (SO₂).

### Step 2: Identify Possible Products
When magnesium reacts with sulfur dioxide, it can form magnesium oxide (MgO) and magnesium sulfide (MgS).

### Step 3: Write the Unbalanced Chemical Equation
The unbalanced equation for the reaction can be written as:
\[ \text{Mg} + \text{SO}_2 \rightarrow \text{MgO} + \text{MgS} \]

### Step 4: Balance the Chemical Equation
1. **Count the Atoms**:
- On the left side, we have:
- Magnesium (Mg): 1
- Sulfur (S): 1
- Oxygen (O): 2
- On the right side, we have:
- Magnesium (Mg): 2 (1 in MgO and 1 in MgS)
- Sulfur (S): 1
- Oxygen (O): 1 (in MgO)

2. **Balance Magnesium**:
To balance magnesium, we need 2 Mg on the left side:
\[ 2\text{Mg} + \text{SO}_2 \rightarrow \text{MgO} + \text{MgS} \]

3. **Balance Oxygen**:
Now we have 2 oxygen atoms on the left side (from SO₂) and 1 on the right side (from MgO). To balance oxygen, we need to adjust the products:
\[ 2\text{Mg} + \text{SO}_2 \rightarrow \text{2MgO} + \text{MgS} \]

4. **Final Check**:
Now, we check:
- Left side: 2 Mg, 1 S, 2 O
- Right side: 3 Mg (2 from MgO and 1 from MgS), 1 S, 2 O

This indicates that we need to adjust the number of magnesium on the left side:
\[ 3\text{Mg} + \text{SO}_2 \rightarrow 2\text{MgO} + \text{MgS} \]

### Final Balanced Equation
The balanced equation is:
\[ 3\text{Mg} + \text{SO}_2 \rightarrow 2\text{MgO} + \text{MgS} \]

### Step 5: Identify the Products
The products of the reaction are magnesium oxide (MgO) and magnesium sulfide (MgS).