`F_(2)` combines with `O_(2)` to form `O_(2) F_(2)` which are

Options

A. diOxygen difluorides
B. Oxides of fluorine
C. Anhydride of HOF
D. Both (2) & (3)

Answer

To solve the question regarding the combination of \( F_2 \) with \( O_2 \) to form \( O_2F_2 \), we will analyze the compound and its classification based on the options provided.

### Step-by-Step Solution:

1. **Identify the Reactants and Product:**
- The reactants are \( F_2 \) (fluorine gas) and \( O_2 \) (oxygen gas).
- The product formed is \( O_2F_2 \).

2. **Determine the Chemical Composition:**
- The formula \( O_2F_2 \) indicates that the compound contains two oxygen atoms and two fluorine atoms.

3. **Classify the Compound:**
- The compound \( O_2F_2 \) can be classified based on its components:
- It contains oxygen and fluorine, which are both nonmetals.
- Compounds formed from oxygen and fluorine are typically referred to as oxides of fluorine.

4. **Evaluate the Options:**
- **Option 1:** Di-oxygen, di-fluoride - This does not accurately describe the compound as it is not simply a diatomic molecule of oxygen and fluorine.
- **Option 2:** Oxides of fluorine - This is a correct classification since \( O_2F_2 \) is indeed an oxide of fluorine.
- **Option 3:** Anhydride of HOF - This is not applicable here as \( O_2F_2 \) does not directly relate to HOF (hydrofluoric acid).
- **Option 4:** 2 and 3 - This option suggests both oxides of fluorine and anhydride of HOF, but since option 3 is incorrect, this option is also incorrect.

5. **Conclusion:**
- The correct classification of \( O_2F_2 \) is as an oxide of fluorine. Therefore, the answer is **Option 2: Oxides of Fluorine**.