`B(OH)_(3)` accept how many `OH^(-)` ions ?

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine how many hydroxide ions (OH⁻) the compound B(OH)₃ can accept, we can follow these steps:

### Step 1: Understand the Structure of B(OH)₃
Boron trihydroxide, B(OH)₃, consists of a boron atom bonded to three hydroxyl (OH) groups. Each hydroxyl group contributes one oxygen and one hydrogen atom.

**Hint:** Visualize the structure of B(OH)₃ to see how boron is connected to the hydroxyl groups.

### Step 2: Analyze the Electron Configuration of Boron
Boron has an atomic number of 5, which means it has 5 electrons. In its valence shell, boron has 3 electrons available for bonding. Therefore, it can form three bonds with the hydroxyl groups.

**Hint:** Remember that boron is in group 13 of the periodic table and typically forms three covalent bonds.

### Step 3: Determine the Covalency of Boron
The maximum covalency of boron is 4. This means that boron can form a total of four bonds. In B(OH)₃, boron is already forming three bonds with the hydroxyl groups.

**Hint:** Consider how many more bonds boron can form beyond the three it has already formed.

### Step 4: Calculate the Number of Additional Hydroxide Ions Accepted
Since boron can form a maximum of four bonds and it currently has three, it can accept one additional hydroxide ion (OH⁻). This will result in the formation of the tetrahydroxyborate ion, B(OH)₄⁻.

**Hint:** Think about how adding one more hydroxide ion will affect the overall charge and structure.

### Step 5: Conclusion
Therefore, B(OH)₃ can accept only one hydroxide ion (OH⁻), resulting in the formation of B(OH)₄⁻.

**Final Answer:** B(OH)₃ can accept **1 OH⁻ ion**.

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