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p pi - p pi multiple bond is seen in...

`p pi - p pi` multiple bond is seen in

A

Mostly carbon

B

All carbon family member

C

Sn but not in carbon

D

Boron family and not in carbon family

Text Solution

AI Generated Solution

The correct Answer is:
To determine where the pπ - pπ multiple bond is seen, we need to analyze the options provided in the question. ### Step-by-Step Solution: 1. **Understanding pπ - pπ Bonds**: - pπ - pπ bonds occur when there is a sideways overlap of p orbitals from two atoms. This type of bond is typically found in elements that can form double or triple bonds. 2. **Analyzing the Options**: - **Option 1: Mostly Carbon**: - Carbon (C) has the electronic configuration of 1s² 2s² 2p². It can form double bonds (C=C) through pπ - pπ overlap. Therefore, this option is correct. - **Option 2: All Carbon Family Members**: - The carbon family (Group 14) includes carbon (C), silicon (Si), germanium (Ge), tin (Sn), and lead (Pb). - While carbon can form pπ - pπ bonds, silicon can also form pπ - dπ bonds due to the presence of vacant d orbitals. However, as we move down the group, the ability to form pπ - pπ bonds decreases due to increasing atomic size and decreasing effective overlap. Thus, this option is partially correct but not entirely true for all members. - **Option 3: Sn but not in Carbon**: - Tin (Sn) does not exhibit pπ - pπ bonding like carbon does. This option is incorrect because carbon does form pπ - pπ bonds. - **Option 4: Boron Family and not in Carbon Family**: - The boron family (Group 13) includes boron (B), aluminum (Al), gallium (Ga), indium (In), and thallium (Tl). Boron can form pπ - pπ bonds, but it does not have vacant d orbitals. Therefore, this option is also incorrect because boron can indeed form pπ - pπ bonds. 3. **Conclusion**: - The correct answer is **Option 1: Mostly Carbon**, as carbon is the primary element where pπ - pπ multiple bonds are prominently observed.
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Assertion : Carbon has unique ability to form p pi-p pi multiple bonds with itself and with other atomic of small size and high electronegativety. Reason : Heaviur elements of group 14th do not form p pi -p pi bonds because their atomic orbital are too large and diffuse to have effective sideways overapping.