`CH_3 Cl + Si overset(Cu "Powder")underset(570 )(to) X overset(2 H_2 O)(to) Y`
Y & X respectively are

Options

A. `(CH_(3))_(2) SiCl_(2) , (CH_(3))_(2) Si(OH)_(2)`
B. `(CH_(3))_(2) Si(OH)_(2) , (CH_(3))_(2) SiCl_(2)`
C. `SiCl_4 , Si(OH)_(4)`
D. `Si(OH)_(4) , SiCl_4`

Answer

To solve the question, we need to analyze the reaction of methyl chloride (CH₃Cl) with silicon (Si) in the presence of copper powder (Cu) at a temperature of 570°C, and then the subsequent reaction of the product with water. Let's break it down step by step.

### Step 1: Identify the Reactants
The reactants in the first reaction are:
- Methyl chloride (CH₃Cl)
- Silicon (Si)
- Copper powder (Cu) as a catalyst

### Step 2: Write the Reaction
When methyl chloride reacts with silicon in the presence of copper powder at high temperature (570°C), the product formed is:
\[ \text{CH}_3\text{Cl} + \text{Si} \xrightarrow{\text{Cu, 570°C}} \text{CH}_3\text{SiCl}_2 \]
This product is known as dimethyldichlorosilane (denoted as X).

### Step 3: Identify the Product X
The product X formed from the reaction is:
\[ \text{X} = \text{CH}_3\text{SiCl}_2 \]
This compound is dimethyldichlorosilane.

### Step 4: React Product X with Water
Next, we take the product X and react it with water (H₂O):
\[ \text{CH}_3\text{SiCl}_2 + 2 \text{H}_2\text{O} \rightarrow \text{CH}_3\text{Si(OH)}_2 + 2 \text{HCl} \]
This reaction results in the formation of:
\[ \text{Y} = \text{CH}_3\text{Si(OH)}_2 \]
This compound is known as dimethylsilenediol.

### Step 5: Identify the Product Y
The product Y formed from the reaction with water is:
\[ \text{Y} = \text{CH}_3\text{Si(OH)}_2 \]

### Final Answer
Thus, the products X and Y are:
- X = Dimethyldichlorosilane (CH₃SiCl₂)
- Y = Dimethylsilenediol (CH₃Si(OH)₂)