Phosphine on reaction with hydrobromic acid gives

Options

A. `PBr_(3)`
B. `P_(2) H_(4) Br_(2)`
C. `PBr_(5)`
D. `PH_(4) Br`

Answer

To solve the question regarding the reaction of phosphine (PH₃) with hydrobromic acid (HBr), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are phosphine (PH₃) and hydrobromic acid (HBr).

2. **Understand the Nature of the Reaction**:
- Phosphine (PH₃) is a weak base and can react with strong acids like HBr. This reaction typically leads to the formation of a phosphonium salt.

3. **Write the Reaction**:
- When phosphine reacts with hydrobromic acid, it accepts a proton (H⁺) from HBr.
- The reaction can be written as:
\[ \text{PH}_3 + \text{HBr} \rightarrow \text{PH}_4\text{Br} \]

4. **Identify the Product**:
- The product formed is phosphonium bromide (PH₄Br). This is a quaternary ammonium compound where phosphine has been protonated.

5. **Conclusion**:
- Therefore, the final answer to the question is that phosphine (PH₃) reacts with hydrobromic acid (HBr) to give phosphonium bromide (PH₄Br).

### Final Answer:
Phosphine on reaction with hydrobromic acid gives phosphonium bromide (PH₄Br).