Nitrogen is obtained when `NaNO_2` reacts with

Options

A. `NH_(4) Cl`
B. `NH_(4) NO_(3)`
C. `(NH_(4))_(2) CO_(3)`
D. `NH_(4) OH`

Answer

To determine which compound reacts with sodium nitrite (NaNO₂) to produce nitrogen gas (N₂), we can analyze the reaction with various ammonium compounds.

### Step-by-Step Solution:

1. **Identify the Reactants**: We are given sodium nitrite (NaNO₂) and need to find a suitable ammonium compound that will react with it to produce nitrogen gas.

2. **Consider the Options**: The options provided are:
- NH₄Cl (Ammonium Chloride)
- NH₄NO₃ (Ammonium Nitrate)
- NH₄₂CO₃ (Ammonium Carbonate)
- NH₄OH (Ammonium Hydroxide)

3. **Analyze Each Option**:
- **Option 1: NH₄Cl** (Ammonium Chloride)
- When NaNO₂ reacts with NH₄Cl, the reaction can be represented as:
\[ \text{NaNO}_2 + \text{NH}_4\text{Cl} \rightarrow \text{N}_2 + 2\text{H}_2\text{O} \]
- This reaction produces nitrogen gas (N₂) along with water.

- **Option 2: NH₄NO₃** (Ammonium Nitrate)
- When NaNO₂ reacts with NH₄NO₃, it does not produce nitrogen gas. Instead, it may lead to other nitrogen oxides or ammonia, but not N₂.

- **Option 3: NH₄₂CO₃** (Ammonium Carbonate)
- Similar to NH₄NO₃, this compound does not yield nitrogen gas when reacted with sodium nitrite.

- **Option 4: NH₄OH** (Ammonium Hydroxide)
- This compound also does not produce nitrogen gas upon reaction with sodium nitrite.

4. **Conclusion**: The only compound that reacts with sodium nitrite to produce nitrogen gas is **NH₄Cl (Ammonium Chloride)**.

### Final Answer:
Nitrogen is obtained when NaNO₂ reacts with **NH₄Cl (Ammonium Chloride)**.

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