The final product formed , when alkaline Kl solution reacts with ozone and water is

Options

A. `l_(2)`
B. `KlO_(3)`
C. `Hl`
D. Reaction will not occur

Answer

To determine the final product formed when alkaline potassium iodide (KI) solution reacts with ozone (O3) and water (H2O), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are alkaline potassium iodide (KI), ozone (O3), and water (H2O).

2. **Understand the Reaction**:
When potassium iodide reacts with ozone in an alkaline medium, the ozone acts as an oxidizing agent. The iodide ions (I-) from KI can be oxidized to iodine (I2).

3. **Write the Balanced Chemical Equation**:
The reaction can be represented as follows:
\[ 2KI + O3 + H2O \rightarrow I2 + O2 + 2KOH \]
In this equation:
- 2 moles of potassium iodide (KI) react with 1 mole of ozone (O3) and 1 mole of water (H2O).
- The products formed are iodine (I2), oxygen (O2), and potassium hydroxide (KOH).

4. **Identify the Final Products**:
From the balanced equation, the final products are iodine (I2), oxygen (O2), and potassium hydroxide (KOH). However, the question specifically asks for the final product formed, which is iodine (I2).

5. **Select the Correct Option**:
Among the given options:
- Option 1: I2 (Correct)
- Option 2: KIO3 (Incorrect)
- Option 3: HI (Incorrect)
- Option 4: Reaction will not occur (Incorrect)

Therefore, the correct answer is **I2**.

### Final Answer:
The final product formed when alkaline KI solution reacts with ozone and water is **I2** (iodine).