What is the product formed when `NH_(3)` reacts with excess of `Cl_(2)` ?

Options

A. `NH_(4) Cl` & HCl
B. `NH_(4) Cl ` & `N_(2)`
C. `NCl_3` & HCl
D. `NH_4 Cl ` & `NCl_3`

Answer

To determine the product formed when ammonia (NH₃) reacts with excess chlorine (Cl₂), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are ammonia (NH₃) and chlorine (Cl₂).

### Step 2: Identify the Reaction
When ammonia reacts with chlorine, especially in excess, it can lead to the formation of nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction of ammonia with excess chlorine is:
\[ 3 \text{NH}_3 + 3 \text{Cl}_2 \rightarrow 3 \text{HCl} + \text{NCl}_3 \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed are nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Conclusion
Thus, the main products formed when ammonia reacts with excess chlorine are nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Final Answer
The correct answer is: **NCl₃ and HCl**.

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