Hybridisation of central N atom in `N_(2) O` is

Options

A. `sp`
B. `sp^(2)`
C. `sp^(3)`
D. sp & `sp^(2)`

Answer

To determine the hybridization of the central nitrogen (N) atom in the compound \( N_2O \), we can follow these steps:

### Step 1: Identify the structure of \( N_2O \)
The molecular structure of \( N_2O \) consists of two nitrogen atoms and one oxygen atom. The central nitrogen atom is bonded to one oxygen atom and one nitrogen atom. The bonding involves a double bond between the central nitrogen and the oxygen, and a double bond between the two nitrogen atoms.

### Step 2: Determine the central atom
In \( N_2O \), the central atom is the nitrogen atom that is bonded to both the other nitrogen and the oxygen atom.

### Step 3: Calculate the steric number
The steric number is calculated using the formula:
\[ \text{Steric Number} = \text{Number of lone pairs on central atom} + \text{Number of sigma bonds formed by central atom} \]

- **Lone pairs**: The central nitrogen atom has no lone pairs because it is involved in double bonds.
- **Sigma bonds**: The central nitrogen forms one sigma bond with the oxygen and one sigma bond with the other nitrogen. Thus, it has 2 sigma bonds.

Now, substituting these values into the formula:
\[ \text{Steric Number} = 0 \text{ (lone pairs)} + 2 \text{ (sigma bonds)} = 2 \]

### Step 4: Determine the hybridization
The hybridization can be determined from the steric number:
- A steric number of 2 corresponds to \( sp \) hybridization.

### Conclusion
The hybridization of the central nitrogen atom in \( N_2O \) is \( sp \).