The compound insoluble in aqueous `NH_(3)` is

Options

A. `Agl`
B. `AgCl`
C. `ZnSO_(4)`
D. `HgCl_(2)`

Answer

To determine which compound is insoluble in aqueous NH₃, we will analyze each option provided in the question.

### Step 1: Identify the Compounds
The compounds given are:
1. AgI (Silver Iodide)
2. AgCl (Silver Chloride)
3. ZnSO₄ (Zinc Sulfate)
4. HgCl₂ (Mercury(II) Chloride)

### Step 2: Analyze Each Compound's Solubility in NH₃

#### Option 1: AgI (Silver Iodide)
- Silver iodide is a silver halide. When AgI is treated with aqueous NH₃, it does not form a soluble complex. Therefore, AgI remains insoluble in aqueous NH₃.

#### Option 2: AgCl (Silver Chloride)
- Silver chloride is also a silver halide. When AgCl is treated with NH₃, it forms a soluble complex, [Ag(NH₃)₂]⁺. Thus, AgCl is soluble in aqueous NH₃.

#### Option 3: ZnSO₄ (Zinc Sulfate)
- Zinc sulfate is soluble in water and also forms a complex with NH₃, specifically [Zn(NH₃)₄]²⁺. Therefore, ZnSO₄ is soluble in aqueous NH₃.

#### Option 4: HgCl₂ (Mercury(II) Chloride)
- Mercury(II) chloride reacts with NH₃ to form a complex, specifically mercury amidochloride, which is also soluble. Thus, HgCl₂ is soluble in aqueous NH₃.

### Conclusion
From the analysis above, we can conclude that the compound that is insoluble in aqueous NH₃ is **AgI (Silver Iodide)**.

### Final Answer
**AgI (Silver Iodide)** is the compound insoluble in aqueous NH₃.

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