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When Cu is reacted with hot concentrated...

When Cu is reacted with hot concentrated solution of `H_(2) SO_(4)` then the gas obtained is

A

`O_(2)`

B

`H_(2)`

C

`SO_2`

D

`SO_3`

Text Solution

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The correct Answer is:
To determine the gas obtained when copper (Cu) reacts with hot concentrated sulfuric acid (H₂SO₄), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants in this reaction are copper (Cu) and hot concentrated sulfuric acid (H₂SO₄). 2. **Write the Reaction**: The reaction between copper and hot concentrated sulfuric acid can be represented as: \[ \text{Cu} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{SO}_2 + \text{H}_2\text{O} \] 3. **Identify the Products**: From the reaction, we can see that the products formed are copper sulfate (CuSO₄), sulfur dioxide (SO₂), and water (H₂O). 4. **Determine the Gas Produced**: Among the products, sulfur dioxide (SO₂) is the gas that is produced during this reaction. 5. **Final Answer**: Therefore, the gas obtained when copper reacts with hot concentrated sulfuric acid is **SO₂ (sulfur dioxide)**.
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Knowledge Check

  • When KHSO_(4) is added into a concentrated solution of H_(2)SO_(4) the acidity of the solution.

    A
    Increases
    B
    Decreases
    C
    remaines
    D
    can't be predicted
  • When oxalic acid is heated with concentrated H_(2) SO_(4) it produces

    A
    `CO, CO_(2),H_(2)O`
    B
    `SO_(2), CO_(2), H_(2)O`
    C
    `CO, SO_(3), H_(2)O`
    D
    `SO_(2), SO_(3), H_(2)O`
  • Zinc reacts with hot and concetrated H_(2)SO_(4) to give

    A
    `H_(2)`
    B
    `SO_(2)`
    C
    `SO_(3)`
    D
    `H_(2)S`
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