In xenon fluorides most reactive in `XeF_(6) , XeF_(4)` and `XeF_(2)` is

Options

A. `XeF_(6)`
B. `XeF_(2)`
C. `XeF_(4)`
D. All are equally reactive

Answer

To determine which xenon fluoride (XeF6, XeF4, or XeF2) is the most reactive, we need to analyze the oxidation states of xenon in each compound. The reactivity of these compounds is often related to the oxidation state of the central atom, xenon in this case. The higher the oxidation state, the more reactive the compound tends to be.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have three xenon fluorides: XeF6, XeF4, and XeF2.

2. **Calculate the Oxidation State of Xenon in Each Compound**:
- For **XeF6**:
- The oxidation state of fluorine (F) is -1.
- The overall charge of the compound is neutral (0).
- Let the oxidation state of xenon be \( x \).
- The equation becomes:
\[ x + 6(-1) = 0 \implies x - 6 = 0 \implies x = +6 \]
- For **XeF4**:
- Using the same method:
- The equation becomes:
\[ x + 4(-1) = 0 \implies x - 4 = 0 \implies x = +4 \]
- For **XeF2**:
- The equation becomes:
\[ x + 2(-1) = 0 \implies x - 2 = 0 \implies x = +2 \]

3. **Summarize the Oxidation States**:
- XeF6: +6
- XeF4: +4
- XeF2: +2

4. **Determine Reactivity Based on Oxidation States**:
- The compound with the highest oxidation state is the most reactive.
- Therefore, since XeF6 has the highest oxidation state of +6, it is the most reactive among the three.

5. **Conclusion**:
- The most reactive xenon fluoride is **XeF6**.

### Final Answer:
The most reactive xenon fluoride is **XeF6**.

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