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A : H(3) PO4 is less acidic than H(3) PO...

A : `H_(3) PO_4` is less acidic than `H_(3) PO_(3)` .
R : Oxidation state of phosphorus in `H_(3) PO_(4) lt H_(3) PO_(3)` .

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion , then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion , then mark (2)

C

If Assertion is true statement but Reason is false , then mark (3)

D

If both Assertion and Reason are false statements , then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that \( H_3PO_4 \) (phosphoric acid) is less acidic than \( H_3PO_3 \) (phosphorous acid). - **Understanding Acidity**: The acidity of a compound is often related to the stability of its conjugate base. A more stable conjugate base corresponds to a stronger acid. - **Structures**: - **\( H_3PO_4 \)**: Has the structure \( P(=O)(OH)_3 \). - **\( H_3PO_3 \)**: Has the structure \( P(=O)(OH)_2(OH) \). ### Step 2: Determine the Conjugate Bases - **Conjugate Base of \( H_3PO_4 \)**: Remove one \( H^+ \) to get \( H_2PO_4^- \). - **Conjugate Base of \( H_3PO_3 \)**: Remove one \( H^+ \) to get \( H_2PO_3^- \). ### Step 3: Stability of Conjugate Bases - **Resonance Structures**: The stability of the conjugate bases can be analyzed through resonance. - **\( H_2PO_4^- \)** has resonance structures that can stabilize the negative charge. - **\( H_2PO_3^- \)** also has resonance structures, but the presence of an additional \( OH \) group in \( H_3PO_3 \) can lead to better charge distribution. ### Step 4: Conclusion on Acidity - The assertion is correct: \( H_3PO_4 \) is indeed less acidic than \( H_3PO_3 \) because the conjugate base \( H_2PO_3^- \) is more stable due to better resonance stabilization. ### Step 5: Analyze the Reason The reason states that the oxidation state of phosphorus in \( H_3PO_4 \) is less than that in \( H_3PO_3 \). - **Calculate Oxidation States**: - For \( H_3PO_4 \): - \( H: +3 \) (3 H atoms) - \( O: -8 \) (4 O atoms, each -2) - Let \( X \) be the oxidation state of phosphorus. - Equation: \( +3 + X - 8 = 0 \) → \( X = +5 \) - For \( H_3PO_3 \): - \( H: +3 \) (3 H atoms) - \( O: -6 \) (3 O atoms, each -2) - Let \( Y \) be the oxidation state of phosphorus. - Equation: \( +3 + Y - 6 = 0 \) → \( Y = +3 \) ### Step 6: Conclusion on Reason - The reason is incorrect: The oxidation state of phosphorus in \( H_3PO_4 \) is +5, which is greater than the oxidation state in \( H_3PO_3 \) (+3). ### Final Conclusion - The assertion is true, but the reason is false. Therefore, the correct answer is that the assertion is true, and the reason is false.
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