`2PbS+3O_2to2PbO+2SO_2`
The above process is callled

Options

A. Roasting
B. Calcination
C. Smelting
D. Leaching

Answer

To determine what the process represented by the reaction \(2PbS + 3O_2 \rightarrow 2PbO + 2SO_2\) is called, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactant is lead sulfide (\(PbS\)) and the products are lead oxide (\(PbO\)) and sulfur dioxide (\(SO_2\)).
- This indicates that a compound containing sulfur (sulfide) is being oxidized.

2. **Understand the Nature of the Reaction**:
- The reaction involves the conversion of a sulfide ore into its oxide form. This is a key characteristic of the roasting process.

3. **Define Roasting**:
- Roasting is a metallurgical process that involves heating sulfide ores in the presence of excess air (or oxygen) to convert them into oxides. During this process, sulfur is released as sulfur dioxide gas.

4. **Differentiate from Other Processes**:
- **Calcination**: This process involves heating carbonates or hydroxides to convert them into oxides, typically in the absence of air.
- **Smelting**: This involves the extraction of metals from their ores by heating them beyond their melting point, often in the presence of reducing agents.
- **Leaching**: This is a process of extracting soluble substances from insoluble materials by using a solvent.

5. **Conclusion**:
- Since the reaction involves the oxidation of a sulfide ore to form an oxide, it is classified as **roasting**.

### Final Answer:
The above process is called **roasting**.

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