Which of the following statement is correct for 3d-transition element

Options

A. All the metals except Sc forms 'MO' oxide
B. All the metals except Zn forms 'MO' oxide
C. All the metals except Zn and Sc form 'MO' oxide
D. All the metals except Mn forms 'MO' oxide

Answer

To determine which statement is correct for 3d-transition elements, we need to analyze the oxidation states and properties of these elements. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the 3d Transition Elements
The 3d transition elements include:
- Scandium (Sc)
- Titanium (Ti)
- Vanadium (V)
- Chromium (Cr)
- Manganese (Mn)
- Iron (Fe)
- Cobalt (Co)
- Nickel (Ni)
- Copper (Cu)
- Zinc (Zn)

### Step 2: Determine the Outermost Electron Configuration
The outermost electron configurations of these elements are as follows:
- Sc: [Ar] 3d¹ 4s²
- Ti: [Ar] 3d² 4s²
- V: [Ar] 3d³ 4s²
- Cr: [Ar] 3d⁵ 4s¹
- Mn: [Ar] 3d⁵ 4s²
- Fe: [Ar] 3d⁶ 4s²
- Co: [Ar] 3d⁷ 4s²
- Ni: [Ar] 3d⁸ 4s²
- Cu: [Ar] 3d¹⁰ 4s¹
- Zn: [Ar] 3d¹⁰ 4s²

### Step 3: Analyze Oxidation States
- **Scandium (Sc)**: Common oxidation state +3.
- **Titanium (Ti)**: Common oxidation states +2, +3, +4.
- **Vanadium (V)**: Common oxidation states +2, +3, +4, +5.
- **Chromium (Cr)**: Common oxidation states +2, +3, +6, but stable at +3.
- **Manganese (Mn)**: Common oxidation states +2, +4, +7.
- **Iron (Fe)**: Common oxidation states +2, +3.
- **Cobalt (Co)**: Common oxidation states +2, +3.
- **Nickel (Ni)**: Common oxidation states +2, +3.
- **Copper (Cu)**: Common oxidation states +1, +2.
- **Zinc (Zn)**: Common oxidation state +2.

### Step 4: Evaluate the Statements
1. **All metals except Scandium form MO**: This statement is generally true as most transition metals form metal oxides.
2. **All metals except Zinc**: This is incorrect because zinc does form oxides.
3. **Zinc and Scandium**: This is incorrect as both can form oxides.
4. **Manganese**: This is too vague and does not provide a complete statement.

### Conclusion
The correct statement is: **All metals except Scandium form metal oxides.**