A: `KMnO_(4)`, is purple in colour due to charge transfer
R: In `MnO_(4)^(-)`. Mn is in + 7 oxidation state and thus has no electron present in d orbitals

Options

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
C. If Assertion is true statement but Reason is false, then mark (3)
D. If both Assertion and Reason are false statements, then mark (4)

Answer

To solve the question, we need to analyze both the assertion (A) and the reason (R) provided in the statement.

### Step 1: Analyze the Assertion (A)
The assertion states that KMnO4 is purple in color due to charge transfer.

- KMnO4 (Potassium permanganate) is known for its distinct purple color. This color arises from electronic transitions that occur due to charge transfer processes.
- There are two types of charge transfer: Ligand to Metal Charge Transfer (LMCT) and Metal to Ligand Charge Transfer (MLCT). In the case of KMnO4, the color is primarily due to LMCT, where electrons from the ligand (O2-) are transferred to the vacant d-orbitals of manganese (Mn).

### Step 2: Analyze the Reason (R)
The reason states that in MnO4^(-), Mn is in the +7 oxidation state and thus has no electrons present in d orbitals.

- To determine the oxidation state of Mn in KMnO4, we can set up the equation based on the charges:
- K (Potassium) has a +1 charge.
- Let the oxidation state of Mn be x. The four oxygen atoms (O) each have a -2 charge, contributing a total of -8.
- The overall charge of the compound is neutral (0).
- Therefore, the equation is: +1 + x + (-8) = 0, which simplifies to x = +7.
- In the +7 oxidation state, the electron configuration of Mn (which is Argon 3d^5 4s^2) indicates that all 7 electrons are removed, resulting in empty 3d and 4s orbitals. Thus, Mn has no electrons in its d-orbitals.

### Step 3: Conclusion
Both the assertion and the reason are correct. The assertion is justified because the purple color of KMnO4 is indeed due to charge transfer, and the reason correctly explains that Mn in the +7 oxidation state has no electrons in the d-orbitals.

### Final Answer
Both the assertion (A) and reason (R) are correct, and the reason provides a correct explanation for the assertion.

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