The compound `PICI_(2) 2NH_(3)` does not react with `AgNO_(3)` This compound can be represented as

Options

A. `[PtCI_(2)](NH_(3))_(2)`
B. `[PtCI_(2)(NH_(3))_(2)]`
C. `[Pt(NH_(3))_(2)]CI_(2)`
D. `[Pt(NH_(3))_(2)CI]CI_(2)`

Answer

To solve the problem regarding the compound \( \text{PtCl}_2 \cdot 2\text{NH}_3 \) that does not react with \( \text{AgNO}_3 \), we need to analyze the coordination sphere and the nature of the ligands involved. Here’s a step-by-step breakdown:

### Step 1: Understand the Coordination Complex
The compound is \( \text{PtCl}_2 \cdot 2\text{NH}_3 \). Here, platinum (Pt) is the central metal atom, and it is coordinated with two chloride ions (Cl) and two ammonia molecules (NH3).

### Step 2: Determine the Coordination Number
In coordination chemistry, the coordination number is the number of ligand atoms that are bonded to the central metal atom. In this case, Pt is surrounded by 4 ligands (2 Cl and 2 NH3), which gives it a coordination number of 4.

### Step 3: Analyze the Reactivity with \( \text{AgNO}_3 \)
The fact that the compound does not react with \( \text{AgNO}_3 \) suggests that the chloride ions are not free to react. This indicates that both Cl ions are likely coordinated within the coordination sphere of the platinum complex, rather than being available as free ions.

### Step 4: Identify the Structure
Given that both chloride ions are inside the coordination sphere, the compound can be represented as:
\[ \text{[PtCl}_2(\text{NH}_3)_2] \]
This indicates that the chloride ions are not available to react with \( \text{AgNO}_3 \) because they are part of the complex.

### Step 5: Confirm the Oxidation State of Platinum
To confirm the oxidation state of platinum in this complex, we can set up the following equation:
- Let the oxidation state of Pt be \( x \).
- The oxidation state of Cl is -1 (for two Cl, it contributes -2).
- The oxidation state of NH3 is 0 (for two NH3, it contributes 0).

Thus, we have:
\[ x - 2 = 0 \]
This gives us \( x = +2 \). Therefore, platinum is in the +2 oxidation state.

### Step 6: Conclude the Structure
The final structure of the compound can be represented as:
\[ \text{[PtCl}_2(\text{NH}_3)_2] \]
This confirms that both Cl ions are within the coordination sphere, which explains the lack of reactivity with \( \text{AgNO}_3 \).

### Final Answer
The compound can be represented as \( \text{[PtCl}_2(\text{NH}_3)_2] \).

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