. How many optical isomers are possible for [MABCD], where M is dsp2 hybridized?

Options

A. 1
B. 2
C. 3
D. Zero

Answer

To determine how many optical isomers are possible for the coordination compound [MABCD], where M is dsp² hybridized, we can follow these steps:

### Step 1: Identify the Hybridization and Geometry
- The given metal M is dsp² hybridized. This hybridization indicates that the geometry of the complex is square planar.

### Step 2: Understand the Structure of the Complex
- In a square planar complex, there are four coordination sites around the metal center. The ligands A, B, C, and D occupy these sites.

### Step 3: Analyze the Ligands
- The ligands A, B, C, and D are all different. This is important because the uniqueness of the ligands can lead to potential optical isomers.

### Step 4: Determine the Plane of Symmetry
- For a molecule to exhibit optical isomerism, it must lack a plane of symmetry. A plane of symmetry is an imaginary plane that divides the molecule into two mirror-image halves.
- In the case of the square planar complex [MABCD], we can analyze the arrangement of the ligands:
- If we try to draw a plane of symmetry, we can see that the arrangement of A, B, C, and D does not allow for a plane that divides the complex into two equal halves. For example, if we place A and B on one side and C and D on the other, they do not mirror each other.

### Step 5: Conclusion on Optical Isomers
- Since the square planar complex [MABCD] has a plane of symmetry, it does not exhibit optical isomerism.
- Therefore, the number of optical isomers for [MABCD] is **0**.

### Final Answer
The number of optical isomers possible for [MABCD] is **0**.

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