In case of high spin situation

Options

A. `Delta_(0)=P`
B. `Delta_(0)gtP`
C. `Delta_(0)ltP`
D. `Delta_(0)P=1`

Answer

### Step-by-Step Solution:

1. **Understanding the Terms**:
- **Δ₀ (Delta naught)**: This is the splitting energy in an octahedral field. It represents the energy difference between the two sets of d-orbitals (T₂g and Eₕ).
- **P (Pairing Energy)**: This is the energy required to pair two electrons in the same orbital.

2. **Concept of Electron Configuration**:
- In a coordination compound, the arrangement of electrons in the d-orbitals is crucial. Depending on the strength of the ligand field, the electrons will either occupy higher energy orbitals or pair up in lower energy orbitals.

3. **High Spin vs Low Spin**:
- **High Spin Situation**: This occurs when Δ₀ < P. In this case, the energy required to pair the electrons is greater than the energy gained from moving to a higher energy orbital. Therefore, electrons will occupy higher energy orbitals instead of pairing.
- **Low Spin Situation**: This occurs when Δ₀ > P. Here, the energy required to pair the electrons is less than the energy gained from occupying higher energy orbitals. Thus, electrons will pair up in the lower energy orbitals.

4. **Electron Filling in High Spin Situation**:
- For a d⁴ configuration in a high spin situation (where Δ₀ < P), the filling will occur as follows:
- The first three electrons will occupy the three degenerate T₂g orbitals (dxy, dyz, dxz).
- The fourth electron will go into the higher energy Eₕ orbital (dx²-y², dz²) instead of pairing with one of the electrons in T₂g orbitals.

5. **Conclusion**:
- In a high spin situation, the electrons prefer to occupy higher energy orbitals rather than pair up in lower energy orbitals due to the relatively low splitting energy compared to pairing energy.