Home
Class 12
CHEMISTRY
An organic compound contains carbon, hyd...

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave`C,38.71%` and `H,9.67%`. The empirical formula of the compound would be `:`

A

`CH_(4)O`

B

`CH_(3)O`

C

`CH_(2)O`

D

CHO

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    AAKASH INSTITUTE|Exercise Assignment(Section-D)(Assertion - Reason Type Questions)|12 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    AAKASH INSTITUTE|Exercise Assignment(SECTION B)|3 Videos
  • MOCK_TEST_20

    AAKASH INSTITUTE|Exercise EXAMPLE|28 Videos
  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLE AND TECHNIQUES

    AAKASH INSTITUTE|Exercise TRY YOURSELF|28 Videos

Similar Questions

Explore conceptually related problems

An organic compound contains carbon, hydrogen and oxygen. Its chemical analysis gave C, 38.71% and H, 9.67%. The empirical formula of compound would be

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C=38.71%,H, 9.67% and O=51.62% . The empirical formula of the compound would be:

An organic compound contains C, H , and O . Its elemental analysis gave C(38.71%) and H (9.67%) . The empirical formula of the compound will be

An organic compound contains carbon, hydrogen and oxygen. If the ratio percentage of C and H is 6:1 calculate the simplest formula of the compound, given that one molecule of the compound contains half as much oxygen as would be required to burn all the carbon and hydrogen atoms in it to CO_2 and H_2O

An organic compound contains carbon, hydrogen and oxygen. IF the percentage of C: the percentage of H=6:1 , calculate the simplest formula of the compound, given that one molecule of the compound contains half as much oxygen as would be required to burn all the corbon and hydrogen atoms in it to CO_2 and H_2O

An organic compound on analysis gave C=39.9 % ,H= 6.7 % and O =53.4 % .The empricial formula of the compound is

An organic compound contains C=40%,H=6.67% and O=53.33% .The empirical formula of compound would be

AAKASH INSTITUTE-ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES -Assignment(SECTION C)
  1. Which of the following species is not electrophilic in nature ?

    Text Solution

    |

  2. The IUPAC name of the compound CH(3)CH=CHC-=CH is

    Text Solution

    |

  3. The IUPAC name of the compound having the formula CH-=C-CH=CH(2) is

    Text Solution

    |

  4. Which of the following compounds will exhibit cis-trans (geometrical )...

    Text Solution

    |

  5. In the hydrocarbon CH(3)-CH = CH-CH(2) -C = CH The state of hybridizat...

    Text Solution

    |

  6. Acidic strength of (a) H(3)CH (b) H(2)C = CH2 (c ) H-C-=C...

    Text Solution

    |

  7. The general molecular formula, which represents the homologous series ...

    Text Solution

    |

  8. The correct order regarding the electronegativity of hybrid orbitals o...

    Text Solution

    |

  9. Which one of the following pairs represent stereoisomerism?

    Text Solution

    |

  10. The best method for the separation of naphthalene and benzoic acid fro...

    Text Solution

    |

  11. The correct order of increasing bond length of C - H ,C - O, C - C and...

    Text Solution

    |

  12. Homolytic fission of the following alkanes forms free radicals CH(3) -...

    Text Solution

    |

  13. Nitrogen detection in an organic compound is carried out by Lassaigne’...

    Text Solution

    |

  14. An organic compound contains carbon, hydrogen and oxygen. Its elementa...

    Text Solution

    |

  15. The number of structural isomers in C(4)H(10)O will be

    Text Solution

    |

  16. The IUPAC name of (CH(3))(2)CH-CH(2)-CH(2)Br is

    Text Solution

    |

  17. Tautomerism is exhibited by

    Text Solution

    |

  18. Which of the following is correct regarding the -I-effect of the subst...

    Text Solution

    |

  19. Increasing order of electrophilic substitution for following compounds...

    Text Solution

    |

  20. IUPAC name of the following is CH(2) = C - CH(2)-CH(2) - C -= CH

    Text Solution

    |