The isomer of `C_(6)H_(14)` which will give maximum number of monochloroderivative is

Options

A. 2,3 -dimethylbutane
B. 2-methylpentane
C. 3-methylpentane
D. Hexane

Answer

To determine the isomer of C6H14 that gives the maximum number of monochloroderivatives, we need to analyze the structural isomers of hexane (C6H14) and their potential for chlorination.

### Step-by-Step Solution:

1. **Identify the Isomers of C6H14**:
The structural isomers of hexane include:
- n-hexane
- 2-methylpentane
- 3-methylpentane
- 2,2-dimethylbutane
- 2,3-dimethylbutane
- 3,3-dimethylbutane

2. **Count the Unique Hydrogen Atoms**:
For each isomer, we need to count the number of unique hydrogen atoms that can be replaced by chlorine during chlorination. The more unique hydrogen atoms, the more monochloroderivatives can be formed.

- **n-hexane**:
- Structure: CH3-CH2-CH2-CH2-CH2-CH3
- Unique H's: 2 (from CH3) + 8 (from CH2) = 10 unique H's
- Monochloroderivatives: 1 (from CH3) + 8 (from CH2) = 9

- **2-methylpentane**:
- Structure: CH3-CH(CH3)-CH2-CH2-CH3
- Unique H's: 3 (from CH3) + 2 (from CH2) + 3 (from CH) = 8 unique H's
- Monochloroderivatives: 3 (from CH3) + 2 (from CH2) + 1 (from CH) = 6

- **3-methylpentane**:
- Structure: CH3-CH2-CH(CH3)-CH2-CH3
- Unique H's: 3 (from CH3) + 2 (from CH2) + 3 (from CH) = 8 unique H's
- Monochloroderivatives: 3 (from CH3) + 2 (from CH2) + 1 (from CH) = 6

- **2,2-dimethylbutane**:
- Structure: CH3-C(CH3)(CH2)-CH3
- Unique H's: 3 (from CH3) + 3 (from CH2) + 1 (from C) = 7 unique H's
- Monochloroderivatives: 3 (from CH3) + 3 (from CH2) + 1 (from C) = 7

- **2,3-dimethylbutane**:
- Structure: CH3-CH(CH3)-C(CH3)-CH3
- Unique H's: 3 (from CH3) + 2 (from CH) + 2 (from CH) = 7 unique H's
- Monochloroderivatives: 3 (from CH3) + 2 (from CH) + 2 (from CH) = 7

- **3,3-dimethylbutane**:
- Structure: CH3-C(CH3)(CH2)-CH3
- Unique H's: 3 (from CH3) + 3 (from CH2) + 1 (from C) = 7 unique H's
- Monochloroderivatives: 3 (from CH3) + 3 (from CH2) + 1 (from C) = 7

3. **Determine the Isomer with Maximum Monochloroderivatives**:
After analyzing all isomers, we find that **n-hexane** produces the maximum number of monochloroderivatives, which is **9**.

### Final Answer:
The isomer of C6H14 which will give the maximum number of monochloroderivatives is **n-hexane**.