Identify the most suitable reagent for the following conversion ?
`CH_(3)-CH_(2)-underset(Br)underset(|)(CH)-CH_(3)overset("Reagent")(rarr)CH_(3)-CH=CH-CH_(3)`

Options

A. Aqueous KOH
B. `(CH_(3))_(3) CO^(-)K^(+)//Delta`
C. alc , KOH /`Delta`
D. All of these

Answer

To identify the most suitable reagent for the conversion of the given compound to an alkene, we need to analyze the reaction step by step.

### Step 1: Identify the Structure
The starting compound is a haloalkane, specifically 1-bromo-2-methylbutane (CH3-CH2-CH(CH3)-Br). The goal is to convert this compound into an alkene, specifically 2-butene (CH3-CH=CH-CH3).

### Step 2: Understand the Mechanism
The conversion involves the elimination of the bromine atom (a leaving group) and a hydrogen atom from the beta carbon (the carbon adjacent to the one bearing the halogen). This type of reaction is typically an elimination reaction (E2 mechanism) where a strong base abstracts a beta hydrogen, leading to the formation of a double bond.

### Step 3: Identify the Beta Hydrogen
In the structure, the beta carbons are the ones adjacent to the carbon with the bromine. The beta hydrogens are the hydrogens attached to these beta carbons. In this case, we have two beta hydrogens available for abstraction.

### Step 4: Choose a Suitable Base
To perform the elimination reaction, we need a strong base that can abstract the beta hydrogen. Common strong bases used in E2 reactions include:
- Sodium hydroxide (NaOH)
- Potassium hydroxide (KOH)
- Sodium ethoxide (NaOEt)
- Potassium tert-butoxide (KOtBu)

Given that we want to favor the formation of the more substituted alkene (2-butene), a bulky base like potassium tert-butoxide (KOtBu) is suitable because it will preferentially abstract the more accessible beta hydrogen.

### Step 5: Write the Reaction
The reaction can be summarized as follows:
1. The strong base (KOtBu) abstracts a beta hydrogen.
2. The bromine atom leaves, resulting in the formation of a double bond.
3. The product formed is 2-butene.

### Conclusion
The most suitable reagent for the conversion of 1-bromo-2-methylbutane to 2-butene is **potassium tert-butoxide (KOtBu)**.

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