`C_(6) H_(5)N2^+Cl^-overset(Cu_(2)Cl_(2)//HCl)(rarr)` , this reaction is named as

Options

A. Sandmeyer
B. Swarts
C. Wurtz-fitting
D. Finkelstein

Answer

To solve the question regarding the reaction of the diazonium salt \( C_6H_5N_2^+Cl^- \) with \( Cu_2Cl_2 \) in the presence of \( HCl \), we need to identify the product formed and the name of the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactant is a diazonium salt, specifically \( C_6H_5N_2^+Cl^- \), which is a benzene ring with a diazonium group (N2^+) and a chloride ion.

2. **Understand the Reaction Conditions**:
The reaction takes place in the presence of \( Cu_2Cl_2 \) and \( HCl \). The copper(I) chloride (\( CuCl \)) acts as a reagent that facilitates the substitution reaction.

3. **Recognize the Type of Reaction**:
In this reaction, the diazonium group (N2^+) is a good leaving group. When it leaves, it is replaced by a chlorine atom from \( Cu_2Cl_2 \).

4. **Determine the Product**:
The product formed from this reaction is chlorobenzene (\( C_6H_5Cl \)). The diazonium group is replaced by a chlorine atom.

5. **Name the Reaction**:
This type of reaction is known as the **Sandmeyer Reaction**. It is a well-known reaction in organic chemistry used to synthesize aryl halides from aryl diazonium salts.

### Final Answer:
The reaction \( C_6H_5N_2^+Cl^- \overset{Cu_2Cl_2/HCl}{\rightarrow} C_6H_5Cl \) is called the **Sandmeyer Reaction**.

---