Which of the following will be readily soluble I water ?

Options

A.
B.
C.
D.

Answer

To determine which of the given compounds will be readily soluble in water, we can follow these steps:

### Step 1: Identify the Compounds
First, we need to identify the compounds that are being compared for their solubility in water. Common examples of haloalkanes and haloarenes include chloroethane, bromoethane, iodoethane, and chlorobenzene.

### Step 2: Understand Water Solubility
Water solubility is influenced by the polarity of the compounds. Polar compounds tend to dissolve well in water due to the ability to form hydrogen bonds with water molecules. Non-polar compounds, on the other hand, do not interact favorably with water and are less soluble.

### Step 3: Analyze the Functional Groups
Haloalkanes and haloarenes contain halogen atoms (F, Cl, Br, I) attached to carbon. The presence of electronegative halogens increases the polarity of the molecule, but the overall structure also matters:
- **Haloalkanes**: Generally, smaller haloalkanes (like chloroethane) are more soluble due to their lower molecular weight and ability to interact with water.
- **Haloarenes**: Compounds like chlorobenzene are less soluble because the aromatic ring is non-polar, which reduces overall polarity.

### Step 4: Compare Solubility
Based on the analysis:
- **Chloroethane** is more likely to be soluble in water compared to **chlorobenzene** because it is a smaller molecule and can engage in hydrogen bonding with water.
- Larger haloalkanes and haloarenes are generally less soluble due to increased hydrophobic character.

### Step 5: Conclusion
From the comparison, we can conclude that **chloroethane** (or any small haloalkane) will be readily soluble in water, while **chlorobenzene** will not be.

### Final Answer
**Chloroethane** is readily soluble in water.

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