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CH(3)-underset(CH(3))underset(|)(CH)-CH=...

`CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to 'A'`
'A' (predominantly) is:

A

`CH_(3) - underset(CH_(3))underset(|)(CH)-underset(Br)underset(|)(CH)-CH_(3)`

B

`CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2)-CH_(2)Br`

C

`CH_(3) - underset(CH_(3))underset(|)(C )overset(Br)overset(|)(C ) - CH_(2) CH_(3)`

D

`CH_(3)-underset(Br)underset(|)(CH) - uderset(CH_(3))underset(|)(CH) - CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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