`CD_(2)` = CH - `CH_(2) - `Br is subjected to `S_(N)1 and S_(N)`2 reactions separately, which of the following statement is correct ?

Options

A. both `S_(N)1 and S_(N)`2 give two products
B. Both `S_(N)1 and S_(N)2` give only product
C. `S_(N)1` gives two products but `S_(N)`2 gives only one product
D. `S_(N)1`gives one product but `S_(N)`2 gives two products

Answer

To solve the problem regarding the reactions of the compound CD₂=CH-CH₂Br with SN1 and SN2 mechanisms, we will analyze each reaction step by step.

### Step 1: Understand the Structure of the Compound
The given compound is CD₂=CH-CH₂Br. Here, we have a bromine atom (Br) attached to a carbon atom that is part of a double bond.

### Step 2: Analyze the SN1 Reaction
1. **SN1 Mechanism Overview**: The SN1 reaction involves two steps:
- **Step 1**: The leaving group (Br) departs, forming a carbocation.
- **Step 2**: A nucleophile attacks the carbocation.

2. **Formation of Carbocation**: When Br leaves, we form a carbocation. The stability of the carbocation is crucial. In this case, we can have resonance stabilization due to the adjacent double bond. The carbocation formed will be:
- CD₂=CH-CH₂⁺ (with a positive charge on the CH₂ adjacent to the double bond).

3. **Possible Products**: The nucleophile can attack the carbocation at two different positions:
- Attack at the carbon with the positive charge (leading to one product).
- Attack at the carbon adjacent to the double bond (leading to a different product).

Thus, in the SN1 reaction, we can expect to form **two products** due to the different positions where the nucleophile can attack.

### Step 3: Analyze the SN2 Reaction
1. **SN2 Mechanism Overview**: The SN2 reaction occurs in a single step where the nucleophile attacks the carbon atom bearing the leaving group (Br) simultaneously as Br leaves.

2. **Nucleophile Attack**: The nucleophile will attack the carbon that is attached to Br:
- This results in the formation of a single product where the nucleophile replaces Br.

Thus, in the SN2 reaction, we can expect to form **only one product** since the nucleophile can only attack the carbon attached to Br.

### Conclusion
- In the SN1 reaction, we have **two products** due to the possibility of nucleophile attack at two different positions.
- In the SN2 reaction, we have **one product** since the nucleophile can only attack one position.

### Final Answer
The correct statement is that there are **two products in SN1** and **one product in SN2**.

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