An ester `A(C_4 H_8 O_2)`, on treatement with excess of methyl magnesium bormide followed by acidification, gives an alcohol `B` as the sole organic product. Alcohol `B` on oxidation with `NaOCl` followed by acidification gives acetice acid. Deduce the structures of `A` and `B`. Show the reactions involved.

Explanation

Esters on treatment with methyl magnesium chloride will give either secondary alcohol or tertiary alcohol. As `3^(@)` alcohols are not easily oxidised hence it must be a secondary alcohol and ester must be an alkyl formate. The various reactions involved are